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2/(x+3)+3/(x-4)=2x-2/x^2-x-12
We move all terms to the left:
2/(x+3)+3/(x-4)-(2x-2/x^2-x-12)=0
Domain of the equation: (x+3)!=0
We move all terms containing x to the left, all other terms to the right
x!=-3
x∈R
Domain of the equation: (x-4)!=0
We move all terms containing x to the left, all other terms to the right
x!=4
x∈R
Domain of the equation: x^2-x-12)!=0We get rid of parentheses
x∈R
2/(x+3)+3/(x-4)-2x+2/x^2+x+12=0
We calculate fractions
-2x+x+(2*(x-4)*x^2)/((x+3)*(x-4)*x^2)+(3*(x+3)*x^2)/((x+3)*(x-4)*x^2)+(2*(x+3)*(x-4))/((x+3)*(x-4)*x^2)+12=0
We calculate terms in parentheses: +(2*(x-4)*x^2)/((x+3)*(x-4)*x^2), so:
2*(x-4)*x^2)/((x+3)*(x-4)*x^2
We multiply all the terms by the denominator
2*(x-4)*x^2)
We multiply parentheses
-8x^3+2x
We do not support expression: x^3
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